(40x^-3y^4)/(5x^-5y^7)

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Solution for (40x^-3y^4)/(5x^-5y^7) equation: 


D( x )

x = 0

5*x^-5*y^7 = 0

x = 0

x = 0

5*x^-5*y^7 = 0

5*x^-5*y^7 = 0

5*x^-5*y^7 = 0 // : 5*y^7

x^-5 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(40*x^-3*y^4)/(5*x^-5*y^7) = 0

8*x^2*y^-3 = 0 // : 8*y^-3

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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